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JEE Main 201815 April
Exam
JEE Main
Year
2018
Date
15 April
Subject
Physics
Chapter
Atomic Physics

JEE Main 2018 · 15 April · Physics · Atomic Physics

The energy required to remove the electron from a singly ionized...

The energy required to remove the electron from a singly ionized Helium atom is 2.22 . 2 times the energy required to remove an electron from helium atom. The total energy required to ionize the Helium atom completely is close to

Options

  1. A34eV34eV
  2. B20eV20eV
  3. C79eV79eV
  4. D109eV109eV

Correct answer

C. 79eV79eV

Step-by-step solution

The energy is required to remove e−{\text{e}}^{-} from singly ionized helium atom=54.4eV= 54.4eV. The energy required to remove e−{\text{e}}^{-} from a helium atom =xeV= xeV, given 54.4eV=2.2x⇒x=24.73eV54.4eV = 2.2x ⇒ x = 24.73eV. The energy required to ionize helium atom =79.13eV≈79eV= 79.13eV \approx 79eV.
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