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JEE Main 20248 AprilMorning Shift
Exam
JEE Main
Year
2024
Date
8 April
Shift
Morning Shift
Subject
Physics
Chapter
Center of Mass, Momentum and Collision

JEE Main 2024 · 8 April · Morning Shift · Physics · Center of Mass, Momentum and Collision

A uniform thin metal plate of mass 10 ~kg with dimensions is shown....

A uniform thin metal plate of mass 10 kg10 \mathrm{~kg} with dimensions is shown. The ratio of x\mathrm{x} and y\mathrm{y} coordinates of center of mass of plate in n9\frac{n}{9}. The value of nn is ________ A uniform thin metal plate of mass 10 ~kg with dimensions is shown. The ratio of x and y coordinates of center of mass

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Step-by-step solution

m1=σ×5=10Kg\mathrm{m}_1=\sigma \times 5=10 \mathrm{Kg} A uniform thin metal plate of mass 10 ~kg with dimensions is shown. The ratio of x and y coordinates of center of mass
A uniform thin metal plate of mass 10 ~kg with dimensions is shown. The ratio of x and y coordinates of center of mass
⇒m1x1+m2x2=m3x310x1+2(1.5)=12(1.5)⇒x1=1.5 cm⇒m1y1+m2y2=m3y310y1+2(1.5)=12×1⇒y1=0.9 cmx1y1=1.50.9=159n=15\begin{aligned} & \Rightarrow \mathrm{m}_1 \mathrm{x}_1+\mathrm{m}_2 \mathrm{x}_2=\mathrm{m}_3 \mathrm{x}_3 \\ & 10 \mathrm{x}_1+2(1.5)=12(1.5) \Rightarrow \mathrm{x}_1=1.5 \mathrm{~cm} \\ & \Rightarrow \mathrm{m}_1 \mathrm{y}_1+\mathrm{m}_2 \mathrm{y}_2=\mathrm{m}_3 \mathrm{y}_3 \\ & 10 \mathrm{y}_1+2(1.5)=12 \times 1 \Rightarrow \mathrm{y}_1=0.9 \mathrm{~cm} \\ & \frac{\mathrm{x}_1}{\mathrm{y}_1}=\frac{1.5}{0.9}=\frac{15}{9} \\ & \mathrm{n}=15\end{aligned}
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