JEE Main 202313 AprilMorning Shift
- Exam
- JEE Main
- Year
- 2023
- Date
- 13 April
- Shift
- Morning Shift
- Subject
- Physics
- Chapter
- Center of Mass, Momentum and Collision
JEE Main 2023 · 13 April · Morning Shift · Physics · Center of Mass, Momentum and Collision
A bullet of 10g leaves the barrel of gun with a velocity of 600m s...
A bullet of leaves the barrel of gun with a velocity of . If the barrel of gun is long and mass of gun is then value of impulse supplied to the gun will be:
Options
- A
- B
- C
- D
Correct answer
A.
Step-by-step solution
The formula to calculate the impulse on the gun is given by
muv\begin{cases}J & = & 10g \times \dfrac{1kg}{1000g} \times \left(600 - 0\right)m{s}^{- 1} \\ & = & 6Ns\end{cases}