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JEE Main202313 Apr 2023Morning ShiftPhysicsCenter of Mass, Momentum and CollisionActual

A bullet of 10 g leaves the barrel of gun with a velocity of 600 m s - 1 . If the barrel of gun is 50 cm long and mass of gun is 3 kg , then value of impulse supplied to the gun will be:

Options

  1. A6   N   s
  2. B3   N   s
  3. C36   N   s
  4. D12   N   s

Correct answer

A. 6   N   s

Step-by-step solution

The formula to calculate the impulse J on the gun is given by J = m v - u       . . . 1 where, m is the mass, u is the initial velocity and v is the final velocity of the bullet. Substitute the values of the known parameters into equation (1) to calculate the required impulse. J = 10   g × 1   kg 1000   g × 600 - 0   m   s - 1 =   6   N   s

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