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JEE Main202330 Jan 2023Evening ShiftPhysicsCenter of Mass, Momentum and CollisionActual

A machine gun of mass 10 kg fires 20 g bullets at the rate of 180 bullets per minute with a speed of 100 m s – 1 each. The recoil velocity of the gun is :

Options

  1. A0 . 02   m   s - 1
  2. B2 . 5   m   s - 1
  3. C1 . 5   m   s - 1
  4. D0 . 6   m   s - 1

Correct answer

D. 0 . 6   m   s - 1

Step-by-step solution

Number of bullets fired per second 180 60 = 3 . Applying momentum conservation, we get 3 20 × 10 - 3 × 100 = 10 v ⇒ v = 0 . 6   m   s - 1

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