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JEE Main 20206 SeptemberEvening Shift
Exam
JEE Main
Year
2020
Date
6 September
Shift
Evening Shift
Subject
Physics
Chapter
Center of Mass, Momentum and Collision

JEE Main 2020 · 6 September · Evening Shift · Physics · Center of Mass, Momentum and Collision

Particle A of mass m _ 1 moving with velocity ( 3 ^ i + ^ j ) ms ^...

Particle AA of mass m1{m}_{1} moving with velocity \left(\sqrt{3}\overset{^}{i} + \overset{^}{j}\right){ms}^{- 1}collideswithanotherparticlecollides with another particleBofmassof mass{m}_{2}whichisatrestinitially.Letwhich is at rest initially. Let\overset{\to}{v}1andand\overset{\to}{v}2bethevelocitiesofparticlesbe the velocities of particlesA and Baftercollisionrespectively.Ifafter collision respectively. If{m}_{1} = 2{m}_{2}andaftercollisionand after collision\overset{\to}{v}1 - \left(\overset{^}{i} + \sqrt{3}\overset{^}{j}\right){ms}^{- 1},theanglebetween, the angle between\overset{\to}{v}1 and \overset{\to}{v}2 is :Particle A of mass m _ 1 moving with velocity ( 3 ^ i + ^ j ) ms ^ - 1 collides with another particle B of mass m _ 2

Options

  1. A15°{15}^{°}
  2. B60°{60}^{°}
  3. C−45°- {45}^{°}
  4. D105°{105}^{°}

Correct answer

D. 105°{105}^{°}

Step-by-step solution

m1u→1+m2u→2=m1v→1+m2v→2{m}_{1}\overset{\to}{u}1 + {m}_{2}\overset{\to}{u}2 = {m}_{1}\overset{\to}{v}1 + {m}_{2}\overset{\to}{v}2

2{m}_{2} ( \sqrt{3}\overset{^}{i} + \overset{^}{j} ) + {m}_{2} \times 0 = 2{m}_{2} ( \overset{^}{i} + \sqrt{3}\overset{^}{j} ) + {m}_{2} \times \overset{\to}{v}2

2\sqrt{3}\overset{^}{i} + 2\overset{^}{j} = 2\overset{^}{i} + 2\sqrt{3}\overset{^}{j} + \overset{\to}{v}2

\overset{\to}{v}2 = ( \sqrt{3} - 1 ) \overset{^}{i} - ( \sqrt{3} - 1 ) \overset{^}{j}

\overset{\to}{v}1 = \overset{^}{i} + \sqrt{3}\overset{^}{j}

Angle between v→1\overset{\to}{v}1 and v→2\overset{\to}{v}2 is 105°{105}^{°}

Particle A of mass m _ 1 moving with velocity ( 3 ^ i + ^ j ) ms ^ - 1 collides with another particle B of mass m _ 2

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