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JEE Main20207 Jan 2020Morning ShiftPhysicsCenter of Mass, Momentum and CollisionActual

Three point particles of masses 1.0 k g , 1.5 kg and 2.5 k g are placed at three corners of a right angle triangle of sides 4.0 c m , 3.0 c m and 5.0 c m as shown in the figure. The centre of mass of the system is at a point:

Options

  1. A0.6   c m right and 2.0   c m above 1   k g mass.
  2. B1.5   c m right and 1.2   c m above 1   k g mass.
  3. C2.0   c m right and 0.9   c m above 1   k g mass.
  4. D0.9   c m right and 2.0   c m above 1   k g mass.

Correct answer

D. 0.9   c m right and 2.0   c m above 1   k g mass.

Step-by-step solution

Take 1   k g mass at origin X c m = 1 × 0 + 1.5 × 3 + 2.5 × 0 5 = 0.9   c m Y c m = 1 × 0 + 1.5 × 0 + 2.5 × 4 5 = 2   c m

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