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JEE Main201912 Apr 2019Evening ShiftPhysicsCenter of Mass, Momentum and CollisionActual

Three particles of masses 50 g , 100 g and 150 g are placed at the vertices of an equilateral triangle of side 1 m (as shown in the figure). The x , y coordinates of the centre of mass will be:

Options

  1. A7 12 m , 3 4 m
  2. B7 12 m , 3 8 m
  3. C3 4 m , 5 12 m
  4. D3 8 m , 7 12 m

Correct answer

A. 7 12 m , 3 4 m

Step-by-step solution

Coordinates of A : 0 , 0 B : 1 2 m , 3 2 m C : ( 1 m , 0 ) Coordinates of center of mass x c m , y c m = 50 × 0 + 150 × 1 2 + 100 × 1 50 + 150 + 100 m , 50 × 0 + 150 × 3 2 + 100 × 0 50 + 150 + 100 m = 7 12 m , 3 4 m

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