It is found that if a neutron suffers an elastic collinear collision with a deuterium at rest, the fractional loss of its energy is P d , while for its similar collision with a carbon nucleus at rest, the fractional loss of energy is P c .

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It is found that if a neutron suffers an elastic collinear collision with a deuterium at rest, the fractional loss of its energy is P d , while for its similar collision with a carbon nucleus at rest, the fractional loss of energy is P c . The values of P d and P c are respectively

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Correct answer: B. 0 . 89 , &#160; 0 . 28

Since, the linear momentum is conserved, u = V 1 + 2 V 2 . e = 1 = V 2 - V 1 u (where e &#8658; the coefficient of restitution), u = V 2 - V 1 V 2 = 2 u 3 &#160; ; V 1 = - u 3 . Initial energy, = 1 2 u 2 . Final energy, = 1 2 &#215; 1 &#215; u 2 9 = u 2 18 . Fractional change = u 2 2 - u 2 18 u 2 2 = 0.88 u = V 1 + 12 V 2 &#8658; 1 = V 2 - V 1 u &#8658; u = V 2 - V 1 &#8658; V 2 = 2 u 13 &#8658; V 1 = - 11 u 13 . Change in energy, = u 2 - 11 u 13 2 &#215; 100 = 0.294

It is found that if a neutron suffers an elastic collinear collision with a deuterium at rest, the fractional loss of its energy is P d , while for its similar collision with a carbon nucleus at rest, the fractional loss of energy is P c . The values of P d and P c are respectively

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