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JEE Main 2005
Exam
JEE Main
Year
2005
Subject
Physics
Chapter
Center of Mass, Momentum and Collision

JEE Main 2005 · Physics · Center of Mass, Momentum and Collision

The block of mass M moving on the frictionless horizontal surface...

The block of mass MM moving on the frictionless horizontal surface collides with a spring of spring constant K\mathrm{K} and compresses it by length L\mathrm{L}. The maximum momentum of the block after collision is The block of mass M moving on the frictionless horizontal surface collides with a spring of spring constant K and

Options

  1. AMKL\sqrt{\mathrm{MK}} \mathrm{L}
  2. BKL22M\frac{\mathrm{KL}^2}{2 \mathrm{M}}
  3. Czero
  4. DML2 K\frac{M L^2}{\mathrm{~K}}

Correct answer

A. MKL\sqrt{\mathrm{MK}} \mathrm{L}

Step-by-step solution

12KL2=P22 m∴P=MKL\frac{1}{2} \mathrm{KL}^2=\frac{\mathrm{P}^2}{2 \mathrm{~m}} \quad \therefore \mathrm{P}=\sqrt{\mathrm{MK}} \mathrm{L}
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