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JEE Main 202311 AprilMorning Shift
Exam
JEE Main
Year
2023
Date
11 April
Shift
Morning Shift
Subject
Physics
Chapter
Communication System

JEE Main 2023 · 11 April · Morning Shift · Physics · Communication System

A transmitting antenna is kept on the surface of the earth. The...

A transmitting antenna is kept on the surface of the earth. The minimum height of receiving antenna required to receive the signal in line of sight at 4km4km distance from it is x×10−2mx \times {10}^{- 2}m. The value of xx is _____.
(Let, radius of earth R=6400kmR = 6400km)

Options

  1. A125125
  2. B12501250
  3. C12.512 . 5
  4. D1.251 . 25

Correct answer

A. 125125

Step-by-step solution

The formula to calculate the range of the antenna is given by

γ=2Rh...(1)\gamma = \sqrt{2Rh} . . . \left(1\right)

Substitute the values of the known parameters into equation (1) and solve to obtain the required height of the antenna.

{4×103=2×6400000×h⇒16×106=2×64×105×h⇒h=(1602×64)m=(108)m=10008×10−2m=125×10−2m\begin{cases}4 \times {10}^{3} & = & \sqrt{2 \times 6400000 \times h} \\ ⇒ & 16 \times {10}^{6} = 2 \times 64 \times {10}^{5} \times h \\ ⇒ & h = \left(\dfrac{160}{2 \times 64}\right)m = \left(\dfrac{10}{8}\right)m \\ = & \dfrac{1000}{8} \times {10}^{- 2}m \\ = & 125 \times {10}^{- 2}m\end{cases}

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