In an experiment to determine the resistance of a given wire using Ohm's law, the voltmeter and ammeter readings are noted as 10 V and 5 A , respectively. The least counts of voltmeter and ammeter are 500 mV and 200 mA

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Correct answer: D. 0.18

Given V = 10 V and I = 5 A Least count of voltmeter, Δ V = 500 mV = 0.5 V Least count of ammeter, Δ I = 200 mA = 0.2 A Resistance is given by Ohm's law: R = (V)/(I) = (10)/(5) = 2 The maximum permissible relative error in resistance is: (Δ R)/(R) = (Δ V)/(V) + (Δ I)/(I) (Δ R)/(2) = (0.5)/(10) + (0.2)/(5) (Δ R)/(2) = 0.05 + 0.04 = 0.09 Δ R = 2 × 0.09 = 0.18 Answer: 0.18

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