An α particle and a proton are accelerated from rest through the same potential difference. The ratio of linear momenta acquired by above two particals will be :

Step-by-step solution

For α particle, m α = 4 a.m.u and charge q α = 2 e . For proton, m p = 1 a.m.u and charge q p = e . As the charged particle are moving through same potential, the kinetic energy acquired by the particle will be equal to electric potential energy i.e., 1 2 m v 2 = q V , where, V is potential. Using the relation between momentum p and kinetic energy, we have p = 2 m E = 2 m q V Then, the ratio of linear momenta of two particles is p α p p = m α q α m p q p = 4 1 × 2 1 = 2 2 1 = 2 2