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JEE Main 20207 JanuaryMorning Shift
Exam
JEE Main
Year
2020
Date
7 January
Shift
Morning Shift
Subject
Physics
Chapter
Dual Nature of Matter

JEE Main 2020 · 7 January · Morning Shift · Physics · Dual Nature of Matter

A beam of electromagnetic radiation of intensity 6.4 × 10 ^ - 5 W /...

A beam of electromagnetic radiation of intensity 6.4×10−5W/cm26.4 \times {10}^{- 5} \text{W} / {\text{cm}}^{2} is comprised of wavelength, λ=310nm\lambda = 310nm . It falls normally on a metal (work function ϕ=2eV\phi = 2eV ) of surface area of 1cm21{cm}^{2} . If one in 103{10}^{3} photons ejects an election, total number of electrons ejected in 1s1s is 10x{10}^{x} . (hc=1240eVnm,1eV=1.6×10−19J),\left(hc = 1240eVnm, 1eV = 1.6 \times {10}^{- 19}J\right), then xx is ___________

Correct answer

0

Step-by-step solution

Energy of photon. E=1240310(nm)=4eV>2eVE = \dfrac{1240}{310\left(\text{nm}\right)} = 4eV > 2eV (So photoelectric effect will take place)
=4×1.6×10−19=6.4×10−19joule= 4 \times 1.6 \times {10}^{- 19} = 6.4 \times {10}^{- 19}joule
Number of photons falling per second
=6.4×10−5×16.4×10−19=1014= \dfrac{6.4 \times {10}^{- 5} \times 1}{6.4 \times {10}^{- 19}} = {10}^{14}
Number of photoelectron emitted per second
=1014103=1011= \dfrac{{10}^{14}}{{10}^{3}} = {10}^{11}
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