JEE Main201910 Apr 2019Morning ShiftPhysicsDual Nature of MatterActual
In a photoelectric effect experiment, the threshold wavelength of light is 380 n m . If the wavelength of incident light is 260 n m , the maximum kinetic energy of emitted electrons will be Given E (in e V ) = 1237 λ ( i n n m )
Options
- A4.5 e V
- B3.0 e V
- C1.5 e V
- D15.1 e V
Correct answer
C. 1.5 e V
Step-by-step solution
From Einstein’s photoelectric equation, K . E m a x = h c λ - h c λ 0 (here, λ 0 = threshold wavelength) = 1237 260 - 1237 380 = 1237 380 - 260 380 × 260 = 1.5 e V