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JEE Main 201910 AprilMorning Shift
Exam
JEE Main
Year
2019
Date
10 April
Shift
Morning Shift
Subject
Physics
Chapter
Dual Nature of Matter

JEE Main 2019 · 10 April · Morning Shift · Physics · Dual Nature of Matter

In a photoelectric effect experiment, the threshold wavelength of...

In a photoelectric effect experiment, the threshold wavelength of light is380nm380nm . If the wavelength of incident light is260nm260nm , the maximum kinetic energy of emitted electrons will be
Given EE (in eVeV ) =1237λ(innm)= \dfrac{1237}{\lambda ( innm )}

Options

  1. A4.5eV4.5eV
  2. B3.0eV3.0eV
  3. C1.5eV1.5eV
  4. D15.1eV15.1eV

Correct answer

C. 1.5eV1.5eV

Step-by-step solution

From Einstein’s photoelectric equation,
K . {E}_\max = \dfrac{hc}{\lambda} - \dfrac{hc}{{\lambda}_{0}} (here, λ0={\lambda}_{0} = threshold wavelength)
=1237260−1237380= \dfrac{1237}{260} - \dfrac{1237}{380}
=1237= 1237\left(\dfrac{380 - 260}{380 \times 260}\right)<br/><br/>= 1.5eV
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