A particle 'P' is formed due to a completely inelastic collision of particles 'x' and 'y' having de-Broglie wavelengths ' λ _ x ' and ' λ _ y ' respectively. If x and y were moving in opposite directions, then the

JEE Main 20199 AprilEvening Shift

JEE Main 2019 · 9 April · Evening Shift · Physics · Dual Nature of Matter

A particle 'P' is formed due to a completely inelastic collision of...

A particle

'P'

is formed due to a completely inelastic collision of particles

'x'

and

'y'

having de-Broglie wavelengths

'{\lambda}_{x}'

and

'{\lambda}_{y}'

respectively. If

x

and

y

were moving in opposite directions, then the de-Broglie wavelength of

'P'

is:

A ${\lambda}_{x} - {\lambda}_{y}$
B $\dfrac{{\lambda}_{x}{\lambda}_{y}}{{\lambda}_{x} + {\lambda}_{y}}$
C $\dfrac{{\lambda}_{x}{\lambda}_{y}}{\left|{\lambda}_{x} - {\lambda}_{y}\right|}$
D ${\lambda}_{x} + {\lambda}_{y}$

C. $\dfrac{{\lambda}_{x}{\lambda}_{y}}{\left|{\lambda}_{x} - {\lambda}_{y}\right|}$

\dfrac{h}{\lambda} = \left|\dfrac{h}{{\lambda}_{x}} - \dfrac{h}{{\lambda}_{y}}\right|

\dfrac{1}{\lambda} = \left|\dfrac{1}{{\lambda}_{x}} - \dfrac{1}{{\lambda}_{y}}\right|

\lambda = \dfrac{{\lambda}_{x}{\lambda}_{y}}{\left|{\lambda}_{x} - {\lambda}_{y}\right|}