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JEE Main 20198 AprilEvening Shift
Exam
JEE Main
Year
2019
Date
8 April
Shift
Evening Shift
Subject
Physics
Chapter
Dual Nature of Matter

JEE Main 2019 · 8 April · Evening Shift · Physics · Dual Nature of Matter

A nucleus A, with a finite de-broglie wavelength λ _ A , undergoes...

A nucleus A,A, with a finite de-broglie wavelength λA,{\lambda}_{A}, undergoes spontaneous fission into two nuclei BB and CC of equal mass. BB flies in the same direction as that of A,A, while CC flies in the opposite direction with a velocity equal to half of that of B.B . The de-Broglie wavelengths λB{\lambda}_{B} and λC{\lambda}_{C} of B and C are respectively:

Options

  1. AλA,λA2{\lambda}_{A}, \dfrac{{\lambda}_{A}}{2}
  2. BλA2,λA\dfrac{{\lambda}_{A}}{2}, {\lambda}_{A}
  3. CλA,2λA{\lambda}_{A}, 2{\lambda}_{A}
  4. D2λA,λA2{\lambda}_{A}, {\lambda}_{A}

Correct answer

B. λA2,λA\dfrac{{\lambda}_{A}}{2}, {\lambda}_{A}

Step-by-step solution

hλA=hλB−hλC\dfrac{h}{{\lambda}_{A}} = \dfrac{h}{{\lambda}_{B}} - \dfrac{h}{{\lambda}_{C}} …(i)
Also λC=2λB{\lambda}_{C} = 2{\lambda}_{B} ...(ii)
From equation (i) & (ii),
1λA=1λB−12λB\dfrac{1}{{\lambda}_{A}} = \dfrac{1}{{\lambda}_{B}} - \dfrac{1}{2{\lambda}_{B}}
λB=λA2;λC=λA{\lambda}_{B} = \dfrac{{\lambda}_{A}}{2}; {\lambda}_{C} = {\lambda}_{A}
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