Two particles move at right angle to each other. Their de Broglie wavelengths are λ 1 and λ 2 respectively. The particles suffer perfectly inelastic collision. The de Broglie wavelength λ of the final particle, is given by:

Question

Two particles move at right angle to each other. Their de Broglie wavelengths are &#955; 1 and &#955; 2 respectively. The particles suffer perfectly inelastic collision. The de Broglie wavelength &#955; of the final particle, is given by:

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Correct answer: D. 1 λ 2 = 1 λ 1 2 + 1 λ 2 2

P 1 → = h λ 1 i ^ , P 2 → = h λ 2 j ^ P → = P 1 → + P 2 → = h λ 1 i ^ + h λ 2 j ^ P → = h 1 λ 1 2 + 1 λ 2 2 h λ = h 1 λ 1 2 + 1 λ 2 2 1 λ 2 = 1 λ 1 2 + 1 λ 2 2

Two particles move at right angle to each other. Their de Broglie wavelengths are λ 1 and λ 2 respectively. The particles suffer perfectly inelastic collision. The de Broglie wavelength λ of the final particle, is given by:

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Correct answer

Step-by-step solution

More from Dual Nature of Matter

Two particles move at right angle to each other. Their de Broglie wavelengths are &#955; 1 and &#955; 2 respectively. The particles suffer perfectly inelastic collision. The de Broglie wavelength &#955; of the final particle, is given by:

Options

Correct answer

Step-by-step solution

More from Dual Nature of Matter

Two particles move at right angle to each other. Their de Broglie wavelengths are λ 1 and λ 2 respectively. The particles suffer perfectly inelastic collision. The de Broglie wavelength λ of the final particle, is given by: