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JEE Main 201912 JanuaryEvening Shift
Exam
JEE Main
Year
2019
Date
12 January
Shift
Evening Shift
Subject
Physics
Chapter
Dual Nature of Matter

JEE Main 2019 · 12 January · Evening Shift · Physics · Dual Nature of Matter

When a certain photosensitive surface is illuminated with a...

When a certain photosensitive surface is illuminated with a monochromatic light of frequency ν,ν, the stopping potential of the photo current is −V02.- \dfrac{{V}_{0}}{2} . When the surface is illuminated by monochromatic light of frequency ν2,\dfrac{ν}{2}, the stopping potential is −V0.- {V}_{0} . The threshold frequency for photoelectric emission is

Options

  1. A5v3\dfrac{5v}{3}
  2. B3v2\dfrac{3v}{2}
  3. C43v\dfrac{4}{3}v
  4. D2v2v

Correct answer

B. 3v2\dfrac{3v}{2}

Step-by-step solution

hν=W+V02ehν = W + \dfrac{{V}_{0}}{2}e

hν2=W+V0e\dfrac{hν}{2} = W + {V}_{0}e

On solving, we get, W=32hνW = \dfrac{3}{2}hν

⇒hν0=32hν⇒ h{ν}_{0} = \dfrac{3}{2}hν

⇒ν0=32ν⇒ {ν}_{0} = \dfrac{3}{2}ν
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