JEE Main201912 Jan 2019Evening ShiftPhysicsDual Nature of MatterActual
When a certain photosensitive surface is illuminated with a monochromatic light of frequency ν , the stopping potential of the photo current is - V 0 2 . When the surface is illuminated by monochromatic light of frequency ν 2 , the stopping potential is - V 0 . The threshold frequency for photoelectric emission is
Options
- A5 v 3
- B3 v 2
- C4 3 v
- D2 v
Correct answer
B. 3 v 2
Step-by-step solution
h ν = W + V 0 2 e h ν 2 = W + V 0 e On solving, we get, W = 3 2 h ν ⇒ h ν 0 = 3 2 h ν ⇒ ν 0 = 3 2 ν