JEE Main202623 January 2026Evening ShiftPhysicsElectromagnetic InductionActual
Suppose a long solenoid of 100 cm length, radius 2 cm having 500 turns per unit length, carries a current I=10 ( t ) A , where =1000 rad . / s . A circular conducting loop (B) of radius 1 cm coaxially slided through the solenoid at a speed v=1 ~cm / s . The r.m.s. current through the loop when the coil B is inserted 10 cm inside the solenoid is / 2 ~A . The value of is _ _ _ _ . [Resistance of the loop =10 ]
Options
- A197
- B80
- C100
- D280
Correct answer
A. 197
Step-by-step solution
EMF induced = A dB dt = A ₀ n di dt = A ₀ n , i₀ t current induced i = R = r^2 ₀ n i₀ R t So i = r^2 ₀ n i₀ 2 R = 10⁻⁴ 4 10⁻⁷ 500 10 10^3 2 10 = 20 ^2 2 10⁻⁶ 197 2 , A