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JEE Main202623 January 2026Morning ShiftPhysicsElectromagnetic InductionActual

A simple pendulum made of mass 10 g and a metallic wire of length 10 cm is suspended vertically in a uniform magnetic field of 2 T. The magnetic field direction is perpendicular to the plane of oscillations of the pendulum. If the pendulum is released from an angle of 60^ with vertical, then maximum induced EMF between the point of suspension and point of oscillation is _ _ _ _ mV. (Take g =10 ~m / s ² )

Correct answer

100

Step-by-step solution

The maximum induced EMF for a rod of length rotating in a magnetic field B is: _ max = B _ max ^2 2 (1) Using energy conservation to find _ max : mg (1 - 60°) = 1 2 (m ^2) _m^2 _m = g = 10 0.1 = 10 rad/s From equation (1): _ max = 2 10 0.01 2 = 0.1 V = 100 mV

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