A conducting circular loop is rotated about its diameter at a constant angular speed of 100 rad / s in a magnetic field of 0.5 T perpendicular to the axis of rotation. When the loop is rotated by 30^ from the horizontal

Correct answer: 14 E = Bω A ω t 15.4 × 10^ -3 = (1)/(2) × 100 × (22)/(7) r^2 × (1)/(2) r = 15.4 × 28 × 10^ -5 22 R = 14 mm

JEE Main 202622 JanuaryEvening Shift

JEE Main 2026 · 22 January · Evening Shift · Physics · Electromagnetic Induction

A conducting circular loop is rotated about its diameter at a...

A conducting circular loop is rotated about its diameter at a constant angular speed of

100 \mathrm{rad} / \mathrm{s}

in a magnetic field of 0.5 T perpendicular to the axis of rotation. When the loop is rotated by

30^{\circ}

from the horizontal position, the induced EMF is 15.4 mV. The radius of the loop is

\_\_\_\_

mm. (Take

\pi=\frac{22}{7}

)

E = B\omega A \sin\omega t

15.4 \times 10^{-3} = \dfrac{1}{2} \times 100 \times \dfrac{22}{7} r^2 \times \dfrac{1}{2}

r = \sqrt{\dfrac{15.4 \times 28 \times 10^{-5}}{22}}

R = 14 \text{ mm}