A conducting circular loop of area 1.0 ~m ² is placed perpendicular to a magnetic field which varies as B= (100 t) Tesla. If the resistance of the loop is 100 , then the average thermal energy dissipated in the loop in one period is _ _ _ _ J.

Step-by-step solution

Flux: = BA = (100t) Wb Induced EMF: = - d dt = -100 (100t) V Induced current: I = R = - (100t) A Power dissipated: P = I^2R = 100 ^2(100t) W Average power: P_ avg = 1 2 100 = 50 W Time period: T = 2 100 s Energy in one period: E = P_ avg T = 50 2 100 = J