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JEE Main 20249 AprilEvening Shift
Exam
JEE Main
Year
2024
Date
9 April
Shift
Evening Shift
Subject
Physics
Chapter
Electromagnetic Induction

JEE Main 2024 · 9 April · Evening Shift · Physics · Electromagnetic Induction

A square loop of side 15 ~cm being moved towards right at a...

A square loop of side 15 cm15 \mathrm{~cm} being moved towards right at a constant speed of 2 cm/s\mathrm{cm} / \mathrm{s} as shown in figure. The front edge enters the 50 cm50 \mathrm{~cm} wide magnetic field at t=t= 0 . The value of induced emf in the loop at t=10 st=10 \mathrm{~s} will be : A square loop of side 15 ~cm being moved towards right at a constant speed of 2 cm / s as shown in figure. The front

Options

  1. A0.3mV0.3 \mathrm{mV}
  2. Bzero
  3. C4.5mV4.5 \mathrm{mV}
  4. D3mV3 \mathrm{mV}

Correct answer

B. zero

Step-by-step solution

At t=10sec\mathrm{t}=10 \mathrm{sec} complete loop is in magnetic field therefore no change in flux A square loop of side 15 ~cm being moved towards right at a constant speed of 2 cm / s as shown in figure. The front e=dϕdt=0\mathrm{e}=\frac{\mathrm{d} \phi}{\mathrm{dt}}=0 e=0\mathrm{e}=0 for complete loop
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