A rod of length 60 ~cm rotates with a uniform angular velocity 20...

A rod of length

60 \mathrm{~cm}

rotates with a uniform angular velocity

20 \mathrm{rad} \mathrm{s}^{-1}

about its perpendicular bisector, in a uniform magnetic filed

0.5 T

. The direction of magnetic field is parallel to the axis of rotation. The potential difference between the two ends of the rod is _____V. A rod of length 60 ~cm rotates with a uniform angular velocity 20 rad s^ -1 about its perpendicular bisector, in a

A rod of length 60 ~cm rotates with a uniform angular velocity 20 rad s^ -1 about its perpendicular bisector, in a

Correct answer

Step-by-step solution

\begin{aligned} & \because \mathrm{V}_0-\mathrm{V}_{\mathrm{A}}=\frac{\mathrm{B} \omega \ell^2}{2} \\ & \mathrm{~V}_0-\mathrm{V}_{\mathrm{B}}=\frac{\mathrm{B} \omega \ell^2}{2} \\ & \therefore \mathrm{V}_{\mathrm{A}}=\mathrm{V}_{\mathrm{B}} \therefore \mathrm{V}_{\mathrm{A}}-\mathrm{V}_{\mathrm{B}}=0\end{aligned}

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