A coil has an inductance of 2 H and resistance of 4 Ω . A 10 V is applied across the coil. The energy stored in the magnetic field after the current has built up to its equilibrium value will be _____ × 10 - 2 J

Step-by-step solution

The data given is L = 2   H R = 4   Ω V = 10   V Using Ohm's law, V = I R , I = 10   V 4   Ω = 5 2   A The energy of an inductor is given by E = 1 2 L I 2 = 1 2 × 2 × 25 4 = 625 × 10 - 2   J