A wire of length 1m moving with velocity 8m s ^ - 1 at right angles...

A wire of length

1m

moving with velocity

8m{s}^{- 1}

at right angles to a magnetic field of

2T

. The magnitude of induced emf, between the ends of wire will be ___________. A wire of length 1m moving with velocity 8m s ^ - 1 at right angles to a magnetic field of 2T . The magnitude of

A wire of length 1m moving with velocity 8m s ^ - 1 at right angles to a magnetic field of 2T . The magnitude of

Options

A $20V$
B $8V$
C $12V$
D $16V$

Correct answer

D. $16V$

Step-by-step solution

A wire of length 1m moving with velocity 8m s ^ - 1 at right angles to a magnetic field of 2T . The magnitude of

The expression of motional emf is $e = BLvsin\theta$ , where, $\theta$ is angle between magnetic field and direction of motion.

Here, $\theta = 90 °$ ,

So, induced emf across the ends of wire is $e = BLvsin90 ° = BLv$

$= 2 \times 1 \times 8 = 16V$

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