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JEE Main 202226 JulyEvening Shift
Exam
JEE Main
Year
2022
Date
26 July
Shift
Evening Shift
Subject
Physics
Chapter
Electromagnetic Induction

JEE Main 2022 · 26 July · Evening Shift · Physics · Electromagnetic Induction

In a coil of resistance 8Ω , the magnetic flux due to an external...

In a coil of resistance 8Ω8Ω, the magnetic flux due to an external magnetic field varies with time as ϕ=23(9−t2)ϕ = \dfrac{2}{3}\left(9 - {t}^{2}\right). The value of total heat produced in the coil, till the flux becomes zero, will be _____ JJ.

Correct answer

0

Step-by-step solution

It is given that magnetic flux ϕ=23(9−t2)ϕ = \dfrac{2}{3}\left(9 - {t}^{2}\right)

For magnetic flux to be zero 0=23(9−t2)⇒t=3s0 = \dfrac{2}{3}\left(9 - {t}^{2}\right) ⇒ t = 3s

According to Faraday's law of electromagnetic induction,

ε=−dϕdt=−23(0−2t)=4t3ε = - \dfrac{dϕ}{dt} = - \dfrac{2}{3}\left(0 - 2t\right) = \dfrac{4t}{3}

Heat produced from 00 to 3s3s,

H=∫03ε2Rdt=∫0316t29×8dt=2JH = {∫}_{0}^{3}\dfrac{{ε}^{2}}{R}dt = {∫}_{0}^{3}\dfrac{16{t}^{2}}{9 \times 8}dt = 2J

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