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JEE Main 202127 AugustEvening Shift
Exam
JEE Main
Year
2021
Date
27 August
Shift
Evening Shift
Subject
Physics
Chapter
Electromagnetic Induction

JEE Main 2021 · 27 August · Evening Shift · Physics · Electromagnetic Induction

A constant magnetic field of 1T is applied in the x > 0 region. A...

A constant magnetic field of 1T1T is applied in the x>0x > 0 region. A metallic circular ring of radius 1m1m is moving with a constant velocity of 1ms−11m{s}^{- 1} along the xx-axis. At t=0st = 0s, the centre OO of the ring is at x=−1mx = - 1m. What will be the value of the induced emf in the ring at t=1st = 1s ? (Assume the velocity of the ring does not change.)

A constant magnetic field of 1T is applied in the x > 0 region. A metallic circular ring of radius 1m is moving with a

Options

  1. A0V0V
  2. B2V2V
  3. C2\piV2\piV
  4. D1V1V

Correct answer

B. 2V2V

Step-by-step solution

Recall the formula of induced E.M.F. in terms of the length of the rod, and uniform magnetic field, E=BvlE = Bvl, here in the case of the ring, l=2Rl = 2R,⇒E=Bv2R⇒ E = Bv2R, when half ring enters, E=1×1×2×1=2VE = 1 \times 1 \times 2 \times 1 = 2V.

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