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JEE Main 20202 SeptemberMorning Shift
Exam
JEE Main
Year
2020
Date
2 September
Shift
Morning Shift
Subject
Physics
Chapter
Electromagnetic Induction

JEE Main 2020 · 2 September · Morning Shift · Physics · Electromagnetic Induction

A circular coil of radius 10cm is placed in a uniform magnetic...

A circular coil of radius 10cm10cm is placed in a uniform magnetic field of 3.0×10−5T3 . 0 \times {10}^{- 5}T with its plane perpendicular to the field initially. It is rotated at constant angular speed about an axis along the diameter of coil and perpendicular to magnetic field so that it undergoes half of rotation in 0.2s0 . 2s. The maximum value of EMF induced (in μV\mu V) in the coil will be close to the integer....

Correct answer

15

Step-by-step solution

Flux as a function of time ϕ=B→⋅A→=ABcos(\omegat)ϕ = \overset{\to}{B} \cdot \overset{\to}{A} = ABcos ( \omegat )

Emf induced,

e=−dϕdt=ABωsin(\omegat)e = \dfrac{- dϕ}{dt} = AB\omega sin ( \omegat )

Max. value of Emf =ABω= AB\omega

=πR2Bω= \pi{R}^{2}B\omega

=3.14×0.1×0.1×3×10−5×π0.2=15= 3 . 14 \times 0 . 1 \times 0 . 1 \times 3 \times {10}^{- 5} \times \dfrac{\pi}{0 . 2} = 15

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