Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JEE Main20208 Jan 2020Morning ShiftPhysicsElectromagnetic InductionActual

At time t = 0 magnetic field of 1000 G a u s s is passing perpendicularly through the area defined by the closed loop shown in the figure. If the magnetic field reduces linearly to 500 G a u s s , in the next 5 s , then induced E M F in the loop is:

Options

  1. A56 μ V
  2. B28 μ V
  3. C48 μ V
  4. D36 μ V

Correct answer

A. 56 μ V

Step-by-step solution

ε = - d ϕ d t = - A d B d t ε = − Δ ϕ Δ t = A Δ B Δ t = 16 × 4 - 4 × 2 1000 - 500 5 × 10 - 4 × 10 - 4 = 56 × 500 5 × 10 - 8 = 56 × 10 - 6 V

Practice Electromagnetic Induction on Quantrex Academy →

More from Electromagnetic Induction

List-I contains four conducting loops lying in the XY plane, as shown in the figures. The loops are rotating about Z axis passing through the point O with time period T in clockwis 2026A 30 cm long solenoid has 10 turns per cm and area of 5 cm ^2 . The current through the solenoid coil varies from 2 A to 4 A in 3.14 s. The e.m.f. induced in the coil is 10⁻⁵ V. Th 2026A square loop of side 2 cm is placed in a time varying magnetic field with magnitude as B = 0.4 (300t) Tesla. The normal to the plane of loop makes an angle of 60° with the field. 2026An inductor of inductance 10 mH having resistance of 100 , is connected to battery of E.M.F. 1.0 V through a switch as shown in the figure below. After switch is closed, the ratio 2026A metal rod of length L rotates about one end at origin with a uniform angular velocity . The magnetic field radially falls off as B(r) = B₀ e^ - r ; being a positive constant. The 2026A circular loop of radius 20 cm and resistance 2 is placed in a time varying magnetic field B = (2t^2 + 2t + 3) T . At t = 0 , for the plane of the loop being perpendicular to the 2026In the given circuit below inductance values of L₁ , L₂ and L₃ are same. The magnetic energy stored in the entire circuit is (U_t) and that stored in the L₂ inductor is (U_l) . U_t 2026A circular current loop of radius R is placed inside square loop of side length L(L >> R) such that they are co-planar and their centers coincide. The permeability of free space is 2026 Full Electromagnetic Induction list All JEE Main PYQs