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JEE Main 201510 AprilOnline
Exam
JEE Main
Year
2015
Date
10 April
Mode
Online
Subject
Physics
Chapter
Electromagnetic Induction

JEE Main 2015 · 10 April · Online · Physics · Electromagnetic Induction

When the current in a coil changes from 5 A to 2 A in 0.1 s , an...

When the current in a coil changes from 5 A\text{5 A} to 2 A\text{2 A} in 0.1 s\text{0}\text{.1 s}, an average voltage of 50V\text{50}\text{V} is produced. The self-inductance of the coil is

Options

  1. A1.67 H\text{1}\text{.67 H}
  2. B6 H\text{6 H}
  3. C3 H\text{3 H}
  4. D0.67 H\text{0}\text{.67 H}

Correct answer

A. 1.67 H\text{1}\text{.67 H}

Step-by-step solution

Magnetic flux

ϕ=LI⇒∆ϕ∆t=L∆I∆tϕ = LI ⇒ \dfrac{∆ ϕ}{∆ t} = L\dfrac{∆ I}{∆ t}

∴(εind)average=∣∆ϕ∆t∣=L∣∆I∆t∣∴ {\left({ε}_{ind}\right)}_{average} = \left|\dfrac{∆ ϕ}{∆ t}\right| = L\left|\dfrac{∆ I}{∆ t}\right|

⇒50=L×5−20.1⇒ 50 = L \times \dfrac{5 - 2}{0.1}

⇒53=L⇒ \dfrac{5}{3} = L

⇒L=1.67H⇒ L = 1.67H
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