JEE Main202523 Jan 2025Morning ShiftPhysicsElectromagnetic WavesActual
The electric field of an electromagnetic wave in free space is E =57 [7.5 10^6 t -5 10⁻³(3 x+4 y) ](4 i -3 j ) N / C . The associated magnetic field in Tesla is
Options
- AB = 57 3 10^8 [7.5 10^6 t -5 10⁻³(3 x+4 y) ]( k )
- BB =- 57 3 10^8 [7.5 10^6 t -5 10⁻³(3 x+4 y) ]( k )
- CB =- 57 3 10^8 [7.5 10^6 t -5 10⁻³(3 x+4 y) ](5 k )
- DB = 57 3 10^8 [7.5 10^6 t -5 10⁻³(3 x+4 y) ](5 k )
Correct answer
C. B =- 57 3 10^8 [7.5 10^6 t -5 10⁻³(3 x+4 y) ](5 k )
Step-by-step solution
aligned & K =3 i +4 j & K = 3 i +4 j 5 & E = 4 i -3 j 5 & ~B = K E & B =- Z & B ₀= E ₀ C = 57 3 10^8 aligned