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JEE Main 20241 FebruaryEvening Shift

Exam: JEE Main
Year: 2024
Date: 1 February
Shift: Evening Shift
Subject: Physics
Chapter: Electromagnetic Waves

JEE Main 2024 · 1 February · Evening Shift · Physics · Electromagnetic Waves

If frequency of electromagnetic wave is 60MHz and it travels in air...

If frequency of electromagnetic wave is

60MHz

and it travels in air along

z

direction then the corresponding electric and magnetic field vectors will be mutually perpendicular to each other and the wavelength of the wave

\left(inm\right)

is :

Options

A $2 . 5$
B $10$
C $5$
D $2$

Correct answer

C. $5$

Step-by-step solution

As speed of electromagnetic wave is given by, $c = f\lambda$ . Therefore,

$\lambda = \dfrac{c}{f} = \dfrac{3 \times {10}^{8}}{60 \times {10}^{6}} = 5m$ .

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