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JEE Main 202311 AprilEvening Shift
Exam
JEE Main
Year
2023
Date
11 April
Shift
Evening Shift
Subject
Physics
Chapter
Electromagnetic Waves

JEE Main 2023 · 11 April · Evening Shift · Physics · Electromagnetic Waves

A plane electromagnetic wave of frequency 20MHz propagates in free...

A plane electromagnetic wave of frequency 20MHz20MHz propagates in free space along xx-direction. At a particular space and time \overset{\to}{E} = 6 . 6\overset{^}{j}V{m}^{- 1}. What is B→\overset{\to}{B} at this point?A plane electromagnetic wave of frequency 20MHz propagates in free space along x -direction. At a particular space and

Options

  1. A2 . 2 \times {10}^{- 8}\overset{^}{k}T
  2. B- 2 . 2 \times {10}^{- 8}\overset{^}{i}T
  3. C- 2 . 2 \times {10}^{- 8}\overset{^}{k}T
  4. D2 . 2 \times {10}^{- 8}\overset{^}{i}T

Correct answer

A. 2 . 2 \times {10}^{- 8}\overset{^}{k}T

Step-by-step solution

It is given that

\overset{\to}{E} = 6 . 6\overset{^}{j} ( V{m}^{- 1} ).

The relation between the electric, magnetic field and speed of light is E→×B→=c→\overset{\to}{E} \times \overset{\to}{B} = \overset{\to}{c}.
A plane electromagnetic wave of frequency 20MHz propagates in free space along x -direction. At a particular space and
Clearly, \overset{\to}{B} = {B}_{0} ( \overset{^}{k} )

Using the relation,
cB0=Ec{B}_{0} = E
⇒B0=(Ec)=6.63×108=2.2×10−8T⇒ {B}_{0} = \left(\dfrac{E}{c}\right) = \dfrac{6 . 6}{3 \times {10}^{8}} = 2 . 2 \times {10}^{- 8}T

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