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JEE Main 202324 JanuaryMorning Shift
Exam
JEE Main
Year
2023
Date
24 January
Shift
Morning Shift
Subject
Physics
Chapter
Electromagnetic Waves

JEE Main 2023 · 24 January · Morning Shift · Physics · Electromagnetic Waves

If → E and → K represent electric field and propagation vectors of...

If E→\overset{\to}{E} and K→\overset{\to}{K} represent electric field and propagation vectors of the EM waves in vacuum, then magnetic field vector is given by:

(ω−\omega - angular frequency)

If → E and → K represent electric field and propagation vectors of the EM waves in vacuum, then magnetic field vector

Options

  1. A1ω(K→×E→)\dfrac{1}{\omega}\left(\overset{\to}{K} \times \overset{\to}{E}\right)
  2. Bω(E→×K→)\omega\left(\overset{\to}{E} \times \overset{\to}{K}\right)
  3. Cω(K→×E→)\omega\left(\overset{\to}{K} \times \overset{\to}{E}\right)
  4. DK→×E→\overset{\to}{K} \times \overset{\to}{E}

Correct answer

A. 1ω(K→×E→)\dfrac{1}{\omega}\left(\overset{\to}{K} \times \overset{\to}{E}\right)

Step-by-step solution

As we know, direction of electromagnetic wave will be in the direction of the vector E→×B→\overset{\to}{E} \times \overset{\to}{B}.

If → E and → K represent electric field and propagation vectors of the EM waves in vacuum, then magnetic field vector

Magnitude of B=Ec=KωEB = \dfrac{E}{c} = \dfrac{K}{\omega}E

⇒B→=1ω(K→×E→)⇒ \overset{\to}{B} = \dfrac{1}{\omega}\left(\overset{\to}{K} \times \overset{\to}{E}\right)

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