JEE Main202226 Jul 2022Evening ShiftPhysicsElectromagnetic WavesActual
The oscillating magnetic field in a plane electromagnetic wave is given by B y = 5 × 10 - 6 sin 1000 π 5 x - 4 × 10 8 t T . The amplitude of electric field will be
Options
- A15 × 10 2 Vm - 1
- B5 × 10 - 6 Vm - 1
- C16 × 10 12 Vm - 1
- D4 × 10 2 Vm - 1
Correct answer
D. 4 × 10 2 Vm - 1
Step-by-step solution
Given here, B y = 5 × 10 - 6 sin 1000 π 5 x - 4 × 10 8 t   T Here, peak value of magnetic field, B 0 = 5 × 10 - 6   T Now the speed of the wave v = ω k = 1000 π × 4 × 10 8 1000 π × 5 = 8 × 10 7   m   s - 1 Using relation between magnetic and electric field, Peak value of electric field is E 0 = B 0 v = 5 × 10 - 6 × 8 × 10 7 = 4 × 10 2   V   m - 1