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JEE Main 202225 JulyEvening Shift
Exam
JEE Main
Year
2022
Date
25 July
Shift
Evening Shift
Subject
Physics
Chapter
Electromagnetic Waves

JEE Main 2022 · 25 July · Evening Shift · Physics · Electromagnetic Waves

Light wave travelling in air along x -direction is given by E _ y =...

Light wave travelling in air along xx-direction is given by Ey=540sinπ×104(x−ct)Vm−1{E}_{y} = 540sin\pi \times {10}^{4}\left(x - ct\right)V{m}^{- 1}. Then, the peak value of magnetic field of wave will be (Given c=3×108ms−1c = 3 \times {10}^{8}m{s}^{- 1})

Options

  1. A18×10−7T18 \times {10}^{- 7}T
  2. B54×10−7T54 \times {10}^{- 7}T
  3. C54×10−8T54 \times {10}^{- 8}T
  4. D18×10−8T18 \times {10}^{- 8}T

Correct answer

A. 18×10−7T18 \times {10}^{- 7}T

Step-by-step solution

Given here, Ey=540sinπ×104(x−ct)Vm−1{E}_{y} = 540sin\pi \times {10}^{4}\left(x - ct\right)V{m}^{- 1}

Here, peak value of electric field, E0=540Vm−1{E}_{0} = 540V{m}^{- 1}

Using relation between magnetic and electric field,

Peak value of magnetic field is B0=E0c=5403×108=18×10−7T{B}_{0} = \dfrac{{E}_{0}}{c} = \dfrac{540}{3 \times {10}^{8}} = 18 \times {10}^{- 7}T

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