JEE Main202225 Jul 2022Evening ShiftPhysicsElectromagnetic WavesActual
Light wave travelling in air along x -direction is given by E y = 540 sin π × 10 4 x - c t V m - 1 . Then, the peak value of magnetic field of wave will be (Given c = 3 × 10 8 m s - 1 )
Options
- A18 × 10 - 7   T
- B54 × 10 - 7   T
- C54 × 10 - 8   T
- D18 × 10 - 8   T
Correct answer
A. 18 × 10 - 7   T
Step-by-step solution
Given here, E y = 540 sin π × 10 4 x - c t   V   m - 1 Here, peak value of electric field, E 0 = 540   V   m - 1 Using relation between magnetic and electric field, Peak value of magnetic field is B 0 = E 0 c = 540 3 × 10 8 = 18 × 10 - 7   T