JEE Main202228 Jun 2022Evening ShiftPhysicsElectromagnetic WavesActual
An EM wave propagating in x -direction has a wavelength of 8 mm . The electric field vibrating y -direction has maximum magnitude of 60 Vm - 1 . Choose the correct equations for electric and magnetic fields if the EM wave is propagating in vacuum :
Options
- AE y = 60 sin π 4 × 10 3 x - 3 × 10 8 t j   ^   V   m - 1 B z = 2 sin π 4 &#
- BE y = 60 sin π 4 × 10 3 x - 3 × 10 8 t   j ^   V   m - 1 B z = 2 × 10 - 7 s
- CE y = 2 × 10 - 7 sin π 4 × 10 3 x - 3 × 10 8 t j ^   V   m - 1 B z = 60 sin `
- DE y = 2 × 10 - 7 sin π 4 × 10 4 x - 4 × 10 8 t j ^   V   m - 1 B z = 60 sin `
Correct answer
B. E y = 60 sin π 4 × 10 3 x - 3 × 10 8 t   j ^   V   m - 1 B z = 2 × 10 - 7 s
Step-by-step solution
Using the relation E → = c B → , where, c is speed of light in vacuum. After analysing each option, we get option B is the correct option as E → B → = 60 2 × 10 - 7 = 3 × 10 8   m   s - 1 .