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JEE Main 202226 JuneEvening Shift
Exam
JEE Main
Year
2022
Date
26 June
Shift
Evening Shift
Subject
Physics
Chapter
Electromagnetic Waves

JEE Main 2022 · 26 June · Evening Shift · Physics · Electromagnetic Waves

Which is the correct ascending order of wavelengths?

Which is the correct ascending order of wavelengths?

Options

  1. Aλvisible<λX−ray<λgamma−ray<λmicrowave{\lambda}_{visible} < {\lambda}_{X - ray} < {\lambda}_{gamma - ray} < {\lambda}_{microwave}
  2. Bλgamma−ray<λX−ray<λvisible<λmicrowave{\lambda}_{gamma - ray} < {\lambda}_{X - ray} < {\lambda}_{visible} < {\lambda}_{microwave}
  3. CλX−ray<λgamma−ray<λvisible<λmicrowave{\lambda}_{X - ray} < {\lambda}_{gamma - ray} < {\lambda}_{visible} < {\lambda}_{microwave}
  4. Dλmicrowave<λvisible<λgamma−ray<λX−ray{\lambda}_{microwave} < {\lambda}_{visible} < {\lambda}_{gamma - ray} < {\lambda}_{X - ray}

Correct answer

B. λgamma−ray<λX−ray<λvisible<λmicrowave{\lambda}_{gamma - ray} < {\lambda}_{X - ray} < {\lambda}_{visible} < {\lambda}_{microwave}

Step-by-step solution

We know that E=hcλ⇒E∝1λE = \dfrac{hc}{\lambda} ⇒ E ∝ \dfrac{1}{\lambda}. Also,

Egamma−ray>EX−ray>Evisible>Emicrowave{E}_{gamma - ray} > {E}_{X - ray} > {E}_{visible} > {E}_{microwave}

Therefore,

λgamma−ray<λX−ray<λvisible<λmicrowave{\lambda}_{gamma - ray} < {\lambda}_{X - ray} < {\lambda}_{visible} < {\lambda}_{microwave}

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