JEE Main202225 Jun 2022Morning ShiftPhysicsElectromagnetic WavesActual
The electric field in an electromagnetic wave is given by E = 56 . 5 sin ω t - x c NC - 1 . Find the intensity of the wave if it is propagating along x -axis in the free space. (Given ϵ 0 = 8 . 85 × 10 - 12 C 2 N - 1 m - 2 )
Options
- A5 . 65 Wm - 2
- B1 . 9 × 10 - 7 Wm - 2
- C4 . 24     Wm - 2
- D56 . 5 Wm - 2
Correct answer
C. 4 . 24     Wm - 2
Step-by-step solution
Given, E = 56 . 5 sin ω t - x c   N   C - 1 Comparing it with the general equation of electromagnetic wave, E = E 0 sin   ω t - k x We have, E 0 = 56 . 5   N   C - 1 So, the intensity will be I = 1 2 ε 0 E 0 2 c = 1 2 × 8 . 85 × 10 - 12 × 56 . 5 2 × 3 × 10 8 = 4 . 24     W   m - 2