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JEE Main202224 Jun 2022Morning ShiftPhysicsElectromagnetic WavesActual

A plane electromagnetic wave travels in a medium of relative permeability 1 . 61 and relative permittivity 6 . 44 . If magnitude of magnetic intensity is 4 . 5 × 10 - 2 A m - 1 at a point, what will be the approximate magnitude of electric field intensity at that point ? (Given : Permeability of free space μ 0 = 4 π × 10 - 7 N A - 2 , speed of light in vacuum c = 3 × 10 8 m s - 1 )

Options

  1. A16 . 96   V   m - 1
  2. B2 . 25 × 10 - 2   V   m - 1
  3. C8 . 48   V   m - 1
  4. D6 . 75 × 10 6   V   m - 1

Correct answer

C. 8 . 48   V   m - 1

Step-by-step solution

The speed of light in a given medium is given by, v = c μ r ε r Magnetic field is B = μ r μ 0 H . Also, the relation between the magnetic field and electric field is given by, E = v B ⇒ E = c μ r ε r × μ r μ 0 H = c ε r × μ r × μ 0 H ⇒ E = 3 × 10 8 6 . 44 × 1 . 61 × 4 π × 10 - 7 × 4 . 5 × 10 - 2 = 8 . 48   V   m - 1

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