The electric field in an electromagnetic wave is given by
$E = \left(50N{C}^{- 1}\right)sin\omega ( t - \dfrac{x}{c} )$
The energy contained in a cylinder of volume $V$ is $5 . 5 \times {10}^{- 12}J .$ The value of $V$ is _______ ${cm}^{3} .$
(given ${ϵ}_{0} = 8 . 8 \times {10}^{- 12}{C}^{2}{N}^{- 1}{m}^{- 2}$ )

Question

The electric field in an electromagnetic wave is given by

E = \left(50N{C}^{- 1}\right)sin\omega ( t - \dfrac{x}{c} )

The energy contained in a cylinder of volume

V

is

5 . 5 \times {10}^{- 12}J .

The value of

V

is _______

{cm}^{3} .

(given

{ϵ}_{0} = 8 . 8 \times {10}^{- 12}{C}^{2}{N}^{- 1}{m}^{- 2}

)

Quantrex Academy · Accepted Answer

Correct answer: 0

Energy density = (1)/(2) ε _ 0 E ^ 2 Energy = (1)/(2) ε _ 0 E ^ 2 × volume 5 . 5 × 10 ^ - 12 = (1)/(2) × 8 . 8 × 10 ^ - 12 × 50 ^ 2 × V V = 500 cm ^ 3

The electric field in an electromagnetic wave is given by E = (50N...

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