JEE Main202131 Aug 2021Morning ShiftPhysicsElectromagnetic WavesActual
The electric field in an electromagnetic wave is given by E = 50   N   C - 1 sin ω ( t - x c ) The energy contained in a cylinder of volume V is 5 . 5 × 10 - 12   J . The value of V is _______ cm 3 . (given ϵ 0 = 8 . 8 × 10 - 12 C 2   N - 1   m - 2 )
Correct answer
0
Step-by-step solution
Energy density = 1 2 ε 0 E 2 Energy = 1 2 ε 0 E 2 × volume 5 . 5 × 10 - 12 = 1 2 × 8 . 8 × 10 - 12 × 50 2 × V V = 500   cm 3