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JEE Main 202116 MarchMorning Shift
Exam
JEE Main
Year
2021
Date
16 March
Shift
Morning Shift
Subject
Physics
Chapter
Electromagnetic Waves

JEE Main 2021 · 16 March · Morning Shift · Physics · Electromagnetic Waves

A plane electromagnetic wave of frequency 500MHz is traveling in a...

A plane electromagnetic wave of frequency 500MHz500MHz is traveling in a vacuum along the y−y -direction. At a particular point in space and time, \overset{\to}{B} = 8 . 0 \times {10}^{- 8}\overset{^}{z}T. The value of the electric field at this point is:(speed of light =3×108ms−1= 3 \times {10}^{8}{ms}^{- 1}) \overset{^}{x}, \overset{^}{y}, \overset{^}{z} are unit vectors along x,yx, y and zz direction.

Options

  1. A- 24\overset{^}{x}V{m}^{- 1}
  2. B2 . 6\overset{^}{x}V{m}^{- 1}
  3. C24\overset{^}{x}V{m}^{- 1}
  4. D- 2 . 6\overset{^}{x}V{m}^{- 1}

Correct answer

A. - 24\overset{^}{x}V{m}^{- 1}

Step-by-step solution

f=5×108Hzf = 5 \times {10}^{8}Hz

EMEM wave is travelling towards + \overset{^}{j}

\overset{\to}{B} = 8 . 0 \times {10}^{- 8}\overset{^}{z}T

\overset{\to}{E} = \overset{\to}{B} \times \overset{\to}{C} = \left(8 \times {10}^{- 8}\overset{^}{z}\right) \times \left(3 \times {10}^{8}\overset{^}{y}\right)

= - 24\overset{^}{x}V{m}^{- 1}

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