A radiation is emitted by 1000W bulb and it generates an electric...

${I}_{avg} = \dfrac{1}{2}{ε}_{0}{E}_{0}^{2}c$

$\dfrac{1 . 25}{100} \times \dfrac{1000}{4\pi{\left(2\right)}^{2}} = \dfrac{1}{2} \times 8 . 85 \times {10}^{- 12} \times 3 \times {10}^{8} \times {E}_{0}^{2}$

${E}_{0}^{2} = 187 . 4$

$∴ {E}_{0} = 13 . 689V{m}^{- 1}$

$= 136 . 89 \times {10}^{- 1}V{m}^{- 1}$

$∴ x = 136 . 89$

Rounding off to nearest integer $x = 137$