JEE Main 20203 SeptemberEvening Shift
- Exam
- JEE Main
- Year
- 2020
- Date
- 3 September
- Shift
- Evening Shift
- Subject
- Physics
- Chapter
- Electromagnetic Waves
JEE Main 2020 · 3 September · Evening Shift · Physics · Electromagnetic Waves
The electric field of a plane electromagnetic wave propagating...
The electric field of a plane electromagnetic wave propagating along the x direction in vacuum is The magnetic field at the moment is:
Options
- A\overset{\to}{B} = \dfrac{{E}_{0}}{\sqrt{{\mu}_{0}{ϵ}_{0}}}\cos ( kx ) \overset{^}{k}
- B\overset{\to}{B} = {E}_{0}\sqrt{{\mu}_{0}{ϵ}_{0}}\cos ( kx ) \overset{^}{j}
- C\overset{\to}{B} = {E}_{0}\sqrt{{\mu}_{0}{ε}_{0}}\cos ( kx ) \overset{^}{k}
- D\overset{\to}{B} = \dfrac{{E}_{0}}{\sqrt{{\mu}_{0}{ϵ}_{0}}}\cos ( kx ) \overset{^}{j}
Correct answer
C. \overset{\to}{B} = {E}_{0}\sqrt{{\mu}_{0}{ε}_{0}}\cos ( kx ) \overset{^}{k}
Step-by-step solution
As the light is propagating in direction
and \overset{^}{E} \times \overset{^}{B} | | \overset{^}{C}
should be in \overset{^}{K} direction