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The magnetic field of an electromagnetic wave is given by: B → = 1.6 × 10 - 6 cos ⁡ 2 × 10 7 z + 6 × 10 15 t 2 i ^ + j ^ W b m 2 The associated electric field will be:

Options

  1. AE → = 4.8 × 10 2 c o s 2 × 10 7 z - 6 × 10 15 t - 2 j ^ + i ^ V m
  2. BE → = 4.8 × 10 2 c o s 2 × 10 7 z + 6 × 10 15 t i ^ - 2 j ^ V m
  3. CE → = 4.8 × 10 2 c o s 2 × 10 7 z + 6 × 10 15 t - i ^ + 2 j ^ V m
  4. DE → = 4.8 × 10 2 c o s 2 × 10 7 z - 6 × 10 15 t 2 i ^ + j ^ V m

Correct answer

C. E → = 4.8 × 10 2 c o s 2 × 10 7 z + 6 × 10 15 t - i ^ + 2 j ^ V m

Step-by-step solution

Given magnetic field, B → = 1.6 × 10 - 6 c o s 2 × 10 7 z + 6 × 10 15 t 2 i ^ + j ^ W b m 2 The relation between magnetic field and electric field is E = c B = ( 3 × 10 8 ) × ( 1.6 × 10 - 6 × 5 ) = 4.8 × 10 2 × 5 The direction of light propagation will be along E → × B → . E → = 4.8 × 10 2 c o s 2 × 10 7 z + 6 × 10 15 t - i ^ + 2 j ^ V m

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