JEE Main201815 Apr 2018Morning ShiftPhysicsElectromagnetic WavesActual
A monochromatic beam of light has a frequency v= 3 2 10¹² ~Hz and is propagating along the direction i + j 2 . It is polarized along the k direction. The acceptable form for the magnetic field is:
Options
- AE₀ C ( i - j 2 ) [10^4 ( i - j 2 ) r - (3 10¹² ) t ]
- BE₀ C ( i - j 2 ) [10^4 ( i + j 2 ) r - (3 10¹² ) t ]
- CE₀ C k [10^4 ( i + j 2 ) r + (3 10¹² ) t ]
- DE₀ C ( i + j + k ) 3 [10^4 ( i + j 2 ) r + (3 10¹² ) t ]
Correct answer
A. E₀ C ( i - j 2 ) [10^4 ( i - j 2 ) r - (3 10¹² ) t ]
Step-by-step solution
No Solution Available