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JEE Main2017PhysicsElectromagnetic WavesActual

Magnetic field in a plane electromagnetic wave is given by, B → = B 0 sin k x + ω t j ^ T . Expression for corresponding electric field will be: (Where c is speed of light)

Options

  1. AE → = - B 0 c sin k x + ω t k ^   V   m - 1
  2. BE → = B 0 c sin k x - ω t k ^   V   m - 1
  3. CE → = B 0 c sin k x + ω t k ^   V   m - 1
  4. DE → = B 0 c sin k x + ω t k ^   V   m - 1

Correct answer

C. E → = B 0 c sin k x + ω t k ^   V   m - 1

Step-by-step solution

For electromagnetic wave speed of light is given by c = E 0 B 0 Electric field is expressed as E 0 = c B 0   ,   E →   i s   ⊥   to direction   x   and direction   o f   B → The expression of electric field is E → = c B 0   s i n ⁡ ( k x + w t ) k ^     V   m - 1

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