JEE Main2015PhysicsElectromagnetic WavesActual
A red L E D emits light at 0 . 1 watt uniformly around it. The amplitude of the electric field of the light at a distance of 1 m from the diode is:
Options
- A7 . 75   V   m - 1
- B1 . 73   V   m - 1
- C2 . 45   V   m - 1
- D5 . 48   V   m - 1
Correct answer
C. 2 . 45   V   m - 1
Step-by-step solution
For a point source of power = P, then intensity at a point at a separation x from the source is, I = P o w e r A r e a = P 4 π x 2 ∵ The average intensity of E.M. wave is given by, I = 1 2 c ε 0 E o 2 ⇒ E 0 = 2 P 4 π ε 0 c   x 2 ∵ 1 4 π ε 0 = 9 × 10 9 ,   P = 0.1   W ,   x = 1   m , c = 3 × 10 8   m   s - 1 ⇒ E 0 = 2 × 0.1 × 9 × 10 9 3 × 10 8 × 1 2 = 6 = 2.45   V   m - 1