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Two charges q ₁ and q ₂ are separated by a distance of 30 cm. A third charge q₃ initially at ' C ' as shown in the figure, is moved along the circular path of radius 40 cm from C to D. If the difference in potential energy due to movement of q₃ from C to D is given by q ₃ ~K 4 ₀ , the value of K is :

Options

  1. A8 q ₂
  2. B6 q ₂
  3. C8 q₁
  4. D6 q ₁

Correct answer

A. 8 q ₂

Step-by-step solution

Potential at C V _ C = kq ₁ 0.4 + kq ₂ 0.5 Potential at D V _ D = kq ₁ 0.4 + kq ₂ 0.1 U = ( V _ D - V _ c ) ( q ₃ )= ( kq ₂ 0.1 - kq ₂ 0.5 ) ( q ₃ ) U =8 kq ₂ q ₃= 8 q ₂ q ₃ 4 ₀

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